How many /15 networks fit
| Parent block | Relationship |
|---|---|
| /8 | 128 × /15 fit inside one /8 |
| /16 | One /15 covers 2 × /16 |
| /24 | One /15 covers 512 × /24 |
A /15 is exactly two /16s or 512 /24s.
Worked example: 198.19.44.1/15
A lab appliance uses 198.19.44.1. Is that inside the benchmarking range 198.18.0.0/15?
- The mask is 255.254.0.0. The second octet (254) is the "interesting" one — the first that is not 255.
- Block size = 256 − 254 = 2. Networks start at multiples of 2 in the second octet: 0, 2, 4, …
- The second octet of 198.19.44.1 is 19. 19 ÷ 2 = 9 remainder 1, so the block starts at 9 × 2 = 18.
- Network = 198.18.0.0 (octets after the second become 0). Broadcast = 18 + 2 − 1 = 19, giving 198.19.255.255 (octets after it become 255).
- Usable hosts: 198.18.0.1 to 198.19.255.254, which is 217 − 2 = 131,070 addresses.
Same thing in binary (network bits | host bits):
Address 11000110.0001001|1.00101100.00000001 Mask 11111111.1111111|0.00000000.00000000 Network 11000110.0001001|0.00000000.00000000
Where /15 is used in real networks
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Benchmarking range 198.18.0.0/15
RFC 2544 reserves 198.18.0.0 to 198.19.255.255 for network device benchmarking. Test tools like traffic generators use it so lab traffic never collides with real addresses.
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Pairing two /16s
If a site was given 10.40.0.0/16 and later needs more room, choosing 10.41.0.0/16 as the second block lets both be summarised as 10.40.0.0/15. Choosing 10.42.0.0/16 would not.
Common /15 mistakes
- Writing
10.41.0.0/15. The second octet of a /15 must be even, so it snaps back to 10.40.0.0/15. - Using 198.18.0.0/15 for a production LAN because it "looks private". It is reserved for benchmarking and some security tools flag it.
/15 FAQ
How many hosts are in a /15?
131,070 usable: 2^17 = 131,072 addresses minus network and broadcast.
What is the range of 198.18.0.0/15?
198.18.0.0 to 198.19.255.255. A /15 covers two values of the second octet, here 18 and 19.
What is the wildcard mask for /15?
0.1.255.255. The mask's second octet is 254, and 255 − 254 = 1.